The correct order of acidity for the followin | vedclass

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Question

(A) The acidity of carboxylic acids depends on the stability of the carboxylate anion formed after the loss of a proton. $1$. $2,6$-Dihydroxybenzoic a

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$I > II > III > IV$

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(A) The acidity of carboxylic acids depends on the stability of the carboxylate anion formed after the loss of a proton. $1$. $2,6$-Dihydroxybenzoic acid $(I)$ is the most acidic because its carboxylate anion is stabilized by intramolecular hydrogen bonding with two $-OH$ groups,which is more effective than the stabilization in salicylic acid $(II)$ which has only one $-OH$ group. $2$. Salicylic acid $(II)$ is more acidic than $m$-hydroxybenzoic acid $(III)$ due to the ortho-effect and strong intramolecular hydrogen bonding. $3$. Between $m$-hydroxybenzoic acid $(III)$ and $p$-hydroxybenzoic acid $(IV)$,the $-OH$ group at the $m$-position exerts only a $-I$ effect (electron-withdrawing),whereas at the $p$-position,it exerts a strong $+R$ effect (electron-donating),which destabilizes the carboxylate anion. Therefore,$III$ is more acidic than $IV$. Thus,the correct order of acidity is $I > II > III > IV$.

The correct order of acidity for the following compounds is:

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