The correct order of atomic radii of group 13 | vedclass

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Question

(C) The atomic radii of group $13$ elements are expected to increase down the group due to the addition of new shells. However, due to the poor shield

Vedclass · Accepted Answer

$Tl > In > Ga > Al$

Vedclass · Answer

(C) The atomic radii of group $13$ elements are expected to increase down the group due to the addition of new shells. However, due to the poor shielding effect of $d$ and $f$ orbitals (lanthanoid contraction), the atomic radius of $Tl$ is slightly larger than or nearly equal to $In$. The actual observed order is $Al Wait, checking the trend: $Al$ $(143 	ext{ pm})$, $Ga$ $(135 	ext{ pm})$, $In$ $(167 	ext{ pm})$, $Tl$ $(170 	ext{ pm})$. Thus, the correct order is $Al  In > Ga > Al$.

List-$I$ (Group $13$ element)	List-$II$ (Metallic radius,$pm$)
$A$. $Al$	$I$. $135$
$B$. $Ga$	$II$. $143$
$C$. $In$	$III$. $170$
$D$. $Tl$	$IV$. $167$

The correct order of atomic radii of group $13$ elements is

Similar Questions

Which of the following statements about anhydrous aluminium chloride is correct?

The first ionization enthalpy values (in $kJ\, mol^{-1}$) of group $13$ elements are:

Element $B$ $Al$ $Ga$ $In$ $Tl$

Ionization Enthalpy $801$ $577$ $579$ $558$ $589$

How would you explain this deviation from the general trend?

Match the following:
List-$I$ (Group $13$ element) List-$II$ (Metallic radius,$pm$)
$A$. $Al$ $I$. $135$
$B$. $Ga$ $II$. $143$
$C$. $In$ $III$. $170$
$D$. $Tl$ $IV$. $167$

The correct answer is:

Basicity of $H_3BO_3$ is :

The correct formula of borax is $Na_2[B_4O_5(OH)_4] \cdot 8H_2O$. If the formula is represented as $Na_2[B_4O_5(OH)_x] \cdot yH_2O$, then the sum of $x$ and $y$ is:

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