The correct order of basic strength of the fo | vedclass

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(C) To determine the basic strength,we analyze the nature of the compounds:$(I)$ $KOH$ is a strong base (alkali metal hydroxide).$(II)$ $Zn(OH)_2$ is

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$I > IV > II > III$

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(C) To determine the basic strength,we analyze the nature of the compounds:$(I)$ $KOH$ is a strong base (alkali metal hydroxide).$(II)$ $Zn(OH)_2$ is an amphoteric hydroxide.$(III)$ $HNO_3$ is a strong acid.$(IV)$ $Ca(OH)_2$ is a strong base (alkaline earth metal hydroxide).Comparing the basicity: $KOH$ (Group $1$) is a stronger base than $Ca(OH)_2$ (Group $2$). $Zn(OH)_2$ is amphoteric,meaning it acts as a weak base compared to strong bases but is more basic than the strong acid $HNO_3$.Therefore,the order of basic strength is $KOH > Ca(OH)_2 > Zn(OH)_2 > HNO_3$,which corresponds to $I > IV > II > III$.

Acid Index	Acid Name and Ionisation Constant $(K_a)$
$1$	Formic acid $(HCOOH)$: $1.8 \times 10^{-4}$
$2$	Hypochlorous acid $(HClO)$: $3.0 \times 10^{-8}$
$3$	Nitrous acid $(HNO_2)$: $4.5 \times 10^{-4}$
$4$	Hydrocyanic acid $(HCN)$: $4.9 \times 10^{-10}$

List-$I$ (Acid)	List-$II$ $(K_a)$
$A$. Phenol	$I$. $1 \times 10^{-13}$
$B$. Benzoic acid	$II$. $3.0 \times 10^{-8}$
$C$. $HClO$	$III$. $1.0 \times 10^{-10}$
$D$. $CH_3COOH$	$IV$. $6.5 \times 10^{-5}$
	$V$. $1.75 \times 10^{-5}$

The correct order of basic strength of the following compounds is:
$(I)$ $KOH$
$(II)$ $Zn(OH)_2$
$(III)$ $HNO_3$
$(IV)$ $Ca(OH)_2$

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The correct order of basic strength of the following compounds is:$(I)$ $KOH$$(II)$ $Zn(OH)_2$$(III)$ $HNO_3$$(IV)$ $Ca(OH)_2$