The correct order of basicity of oxides of vanadium is

  • A
    $V_2O_3 > V_2O_4 > V_2O_5$
  • B
    $V_2O_3 > V_2O_5 > V_2O_4$
  • C
    $V_2O_5 > V_2O_4 > V_2O_3$
  • D
    $V_2O_4 > V_2O_3 > V_2O_5$

Explore More

Similar Questions

How are transition metals and their oxides used in industrial processes?

All $Cu(II)$ halides are known,except the iodide. The reason for this is that:

Addition of high proportions of manganese makes steel useful in making rails of railroads,because manganese

Which pair of compounds contains both metals in their highest possible oxidation state?

Give examples and suggest reasons for the following features of the transition metal chemistry:
$(i)$ The lowest oxide of transition metal is basic,the highest is amphoteric/acidic.
$(ii)$ $A$ transition metal exhibits highest oxidation state in oxides and fluorides.
$(iii)$ The highest oxidation state is exhibited in oxoanions of a metal.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo