The correct order of boiling point is :- | vedclass

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Question

(A) The boiling point depends on the intermolecular forces of attraction. $(c)$ $CH_3(CH_2)_3OH$ (n-butanol) has intermolecular hydrogen bonding,which

Vedclass · Accepted Answer

$c > b > a > d$

Vedclass · Answer

(A) The boiling point depends on the intermolecular forces of attraction. $(c)$ $CH_3(CH_2)_3OH$ (n-butanol) has intermolecular hydrogen bonding,which is the strongest interaction,so it has the highest boiling point. $(b)$ $C_2H_5-O-C_2H_5$ (diethyl ether) has dipole-dipole interactions. $(a)$ $n$-Butane $(C_4H_{10})$ and $(d)$ $CH_3-CH_3$ (ethane) are alkanes and have only weak London dispersion forces. Comparing $(a)$ and $(d)$,$n$-butane has a higher molecular mass than ethane,so it has a higher boiling point. Thus,the order of boiling point is: $(c) > (b) > (a) > (d)$.

Column-$I$	Column-$II$	Column-$III$
$(A) \ HO-CH_2-CH_2OH$	$(1) \ \text{sec-Butyl alcohol}$	$(i) \ \text{Ethane-1,2-diol}$
$(B) \ CH_3-CH(OH)-CH_2CH_3$	$(2) \ \text{Isopropyl alcohol}$	$(ii) \ \text{2,2-Dimethylpropan-1-ol}$
$(C) \ CH_3-CH(OH)-CH_3$	$(3) \ \text{Ethylene glycol}$	$(iii) \ \text{Butan-2-ol}$
$(D) \ (CH_3)_3C-CH_2OH$	$(4) \ \text{Neopentyl alcohol}$	$(iv) \ \text{Propan-2-ol}$

The correct order of boiling point is $:-$

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