The correct order of boiling points of the co | vedclass

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(C) The boiling points of organic compounds depend on the strength of intermolecular forces. $1$. Propan-$1$-ol $(CH_3CH_2CH_2OH)$ exhibits strong int

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$B > D > C > A$

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(C) The boiling points of organic compounds depend on the strength of intermolecular forces. $1$. Propan-$1$-ol $(CH_3CH_2CH_2OH)$ exhibits strong intermolecular hydrogen bonding,resulting in the highest boiling point. $2$. Propanone $(CH_3COCH_3)$ and Propanal $(CH_3CH_2CHO)$ are polar compounds with dipole-dipole interactions. Propanone has a higher boiling point than Propanal due to a larger dipole moment. $3$. Methoxy ethane $(CH_3OCH_2CH_3)$ is an ether with weak dipole-dipole interactions and no hydrogen bonding,resulting in the lowest boiling point. The order is: Propan-$1$-ol $(B)$ > Propanone $(D)$ > Propanal $(C)$ > Methoxy ethane $(A)$. Therefore,the correct order is $B > D > C > A$.

The correct order of boiling points of the compounds given below is-
$A$) Methoxy ethane
$B$) Propan-$1$-ol
$C$) Propanal
$D$) Propanone

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The correct order of boiling points of the compounds given below is- $A$) Methoxy ethane $B$) Propan-$1$-ol $C$) Propanal $D$) Propanone