The correct order of bond angle is:

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Question

(B) In $PX_3$ molecules,the central atom $P$ is $sp^3$ hybridized with one lone pair.As the electronegativity of the surrounding halogen atom decrease

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$PF_3 < PCl_3 < PBr_3 < PI_3$

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(B) In $PX_3$ molecules,the central atom $P$ is $sp^3$ hybridized with one lone pair.As the electronegativity of the surrounding halogen atom decreases $(F > Cl > Br > I)$,the bond pair electrons move further away from the central atom.According to the $VSEPR$ theory,as the size of the surrounding atom increases,the bond pair-bond pair repulsion decreases,but the bond angle increases due to the decrease in electronegativity of the surrounding atoms.Therefore,the correct order of bond angle is $PI_3 > PBr_3 > PCl_3 > PF_3$.

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