The correct order of bond angles in the follo | vedclass

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Question

(A) $1$. Determine the hybridization and geometry of each species:- $CO_2$: $sp$ hybridization,linear,bond angle = $180^{\circ}$.- $NH_4^{+}$: $sp^3$

Vedclass · Accepted Answer

$H_2O < NH_3 < NH_4^{+} < CO_2$

Vedclass · Answer

(A) $1$. Determine the hybridization and geometry of each species:- $CO_2$: $sp$ hybridization,linear,bond angle = $180^{\circ}$.- $NH_4^{+}$: $sp^3$ hybridization,tetrahedral,bond angle = $109.5^{\circ}$.- $NH_3$: $sp^3$ hybridization,trigonal pyramidal,one lone pair,bond angle = $107^{\circ}$.- $H_2O$: $sp^3$ hybridization,bent,two lone pairs,bond angle = $104.5^{\circ}$.$2$. Comparing the bond angles: $104.5^{\circ} (H_2O) $3$. The correct order is $H_2O < NH_3 < NH_4^{+} < CO_2$.

The correct order of bond angles in the following compounds/species is:

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