The correct order of decreasing acid strength | vedclass

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(C) The acid strength depends on the stability of the conjugate base formed after the loss of $H^+$ ion.Electron-withdrawing groups ($-I$ effect) stab

Vedclass · Accepted Answer

$2 > 1 > 4 > 3$

Vedclass · Answer

(C) The acid strength depends on the stability of the conjugate base formed after the loss of $H^+$ ion.Electron-withdrawing groups ($-I$ effect) stabilize the carboxylate anion,thereby increasing acidity.Fluorine $(F)$ has a stronger $-I$ effect than Chlorine $(Cl)$.Therefore,trifluoroacetic acid $(CF_3COOH)$ is a stronger acid than trichloroacetic acid $(CCl_3COOH)$.Formic acid $(HCOOH)$ is stronger than acetic acid $(CH_3COOH)$ because the methyl group in acetic acid exerts a $+I$ effect,which destabilizes the carboxylate anion.The order of decreasing acid strength is: Trifluoroacetic acid $(2)$ $>$ Trichloroacetic acid $(1)$ $>$ Formic acid $(4)$ $>$ Acetic acid $(3)$.Thus,the correct order is $2 > 1 > 4 > 3$.

The correct order of decreasing acid strength of the following acids is:
$(1)$ Trichloroacetic acid
$(2)$ Trifluoroacetic acid
$(3)$ Acetic acid
$(4)$ Formic acid

Similar Questions

Which acid is the strongest?

In the following reaction sequence,identify product $Q$ and reagent $R$:

For the following three esters, the order of rates of alkaline hydrolysis is:
$(I)$ $p-NO_2-C_6H_4-COOCH_3$
$(II)$ $p-CH_3O-C_6H_4-COOCH_3$
$(III)$ $p-CH_3-C_6H_4-COOCH_3$

The major product formed in the following reaction is
$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$

Correct order of $pK_{a}$ of given compounds is $:-$
$(P) \ CH_{3}COOH$
$(Q) \ FCH_{2}COOH$
$(R) \ ClCH_{2}COOH$
$(S) \ C_{2}H_{5}COOH$

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The correct order of decreasing acid strength of the following acids is:$(1)$ Trichloroacetic acid$(2)$ Trifluoroacetic acid$(3)$ Acetic acid$(4)$ Formic acid