The correct order of dehydration of alcohols is
- A$1^{\circ} > 2^{\circ} > 3^{\circ}$
- B$3^{\circ} > 2^{\circ} > 1^{\circ}$
- C$2^{\circ} > 1^{\circ} > 3^{\circ}$
- D$1^{\circ} > 3^{\circ} > 2^{\circ}$
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Similar Questions
Which compound will give a yellow precipitate on reaction with sodium hypoiodite?
In the reaction $R-OH + HX \to RX + H_2O$,what is the order of reactivity of alcohols?
Medium
View SolutionIdentify the alcohol that reacts immediately with Lucas reagent.
What is the correct order of reactivity of the following alcohols towards $H-X$?
$(I) \; CH_2 = CH - OH$
$(II) \; CH_2 = CH - CH_2OH$
$(III) \; CH_3 - CH_2 - OH$
$(IV) \; CH_3 - CH(OH) - CH_3$
$(I) \; CH_2 = CH - OH$
$(II) \; CH_2 = CH - CH_2OH$
$(III) \; CH_3 - CH_2 - OH$
$(IV) \; CH_3 - CH(OH) - CH_3$
Difficult
View SolutionProf. Sandy Gilbert asked his students to prepare $2$-chloropropane by different methods:
Kaushal's method: $CH_3-CH(OH)-CH_3 \xrightarrow{KCl}$
Preeti's method: $CH_3-CH=CH_2 \xrightarrow{Cl_2 + H_2O}$
Raghav's method: $CH_3-CH(OH)-CH_3 \xrightarrow[Pyridine]{SOCl_2}$
Kaushal's method: $CH_3-CH(OH)-CH_3 \xrightarrow{KCl}$
Preeti's method: $CH_3-CH=CH_2 \xrightarrow{Cl_2 + H_2O}$
Raghav's method: $CH_3-CH(OH)-CH_3 \xrightarrow[Pyridine]{SOCl_2}$
Medium
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