The correct order of dipole moment is

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(A) The dipole moment of $CH_4$ is $0 \ D$ because it is a non-polar tetrahedral molecule.The dipole moment of $NF_3$ is $0.2 \ D$ due to the opposing

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$CH_4 < NF_3 < NH_3 < H_2O$

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(A) The dipole moment of $CH_4$ is $0 \ D$ because it is a non-polar tetrahedral molecule.The dipole moment of $NF_3$ is $0.2 \ D$ due to the opposing directions of the lone pair and $N-F$ bond dipoles.The dipole moment of $NH_3$ is $1.47 \ D$ because the lone pair and $N-H$ bond dipoles reinforce each other.The dipole moment of $H_2O$ is $1.85 \ D$ due to its bent geometry and high electronegativity difference.Therefore,the correct order of increasing dipole moment is $CH_4 < NF_3 < NH_3 < H_2O$.

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