The correct order of electronegativity of car | vedclass

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Question

(B) Electronegativity is directly proportional to the percentage of $s$-character in the hybrid orbital. As the percentage of $s$-character increases,

Vedclass · Accepted Answer

$sp > sp^2 > sp^3$

Vedclass · Answer

(B) Electronegativity is directly proportional to the percentage of $s$-character in the hybrid orbital. As the percentage of $s$-character increases,the hybrid orbital is held more closely to the nucleus,increasing the electron-attracting tendency. The percentage of $s$-character in different hybridization states of carbon is: $sp = 50\%$,$sp^2 = 33.3\%$,and $sp^3 = 25\%$. Therefore,the order of electronegativity is $sp > sp^2 > sp^3$.

The correct order of electronegativity of carbon in various hybridization states:

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