The correct order of increasing s-character ( | vedclass

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(A) The hybridizations and corresponding $s-$character percentages are as follows:$I. CO_3^{2-}: sp^2$ hybridization,$s-$character $= \frac{1}{3} 	im

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$II < III < IV < I < V$

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(A) The hybridizations and corresponding $s-$character percentages are as follows:$I. CO_3^{2-}: sp^2$ hybridization,$s-$character $= \frac{1}{3} 	imes 100 \approx 33.3\%$$II. XeF_4: sp^3d^2$ hybridization,$s-$character $= \frac{1}{6} 	imes 100 \approx 16.6\%$$III. I_3^-: sp^3d$ hybridization,$s-$character $= \frac{1}{5} 	imes 100 = 20\%$$IV. NCl_3: sp^3$ hybridization,$s-$character $= \frac{1}{4} 	imes 100 = 25\%$$V. BeCl_2: sp$ hybridization,$s-$character $= \frac{1}{2} 	imes 100 = 50\%$Comparing the percentages: $16.6\% (II) Therefore,the correct increasing order is $II < III < IV < I < V$.

The correct order of increasing $s-$character (in percentage) in the hybrid orbitals of the following molecules/ions is:
$(I)$ $CO_3^{2-}$ $(II)$ $XeF_4$ $(III)$ $I_3^-$ $(IV)$ $NCl_3$ $(V)$ $BeCl_2$

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The correct order of increasing $s-$character (in percentage) in the hybrid orbitals of the following molecules/ions is:$(I)$ $CO_3^{2-}$ $(II)$ $XeF_4$ $(III)$ $I_3^-$ $(IV)$ $NCl_3$ $(V)$ $BeCl_2$