The correct order of increasing basic nature | vedclass

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Question

(C) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom.$1$. The alkyl group $(CH_3-)$ is an electro

Vedclass · Accepted Answer

$NH_3 < CH_3NH_2 < (CH_3)_2NH$

Vedclass · Answer

(C) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom.$1$. The alkyl group $(CH_3-)$ is an electron-donating group that exhibits the $+I$ effect,which increases the electron density on the nitrogen atom.$2$. Ammonia $(NH_3)$ has no alkyl groups,so it is the least basic among the three.$3$. Methylamine $(CH_3NH_2)$ has one methyl group,while dimethylamine $((CH_3)_2NH)$ has two methyl groups.$4$. Since $(CH_3)_2NH$ has two electron-donating groups,it has higher electron density on the nitrogen atom compared to $CH_3NH_2$.Therefore,the correct order of increasing basicity is $NH_3 < CH_3NH_2 < (CH_3)_2NH$.

List $I$ (Amines)	List $II$ $(pK_{b})$
$A$. Aniline	$I$. $3.25$
$B$. Ethanamine	$II$. $3.00$
$C$. $N$-Ethylethanamine	$III$. $9.38$
$D$. $N,N$-Diethylethanamine	$IV$. $3.29$

The correct order of increasing basic nature for the bases $NH_3$,$CH_3NH_2$ and $(CH_3)_2NH$ is

Similar Questions

The correct stability order of the following diazonium salts is:

Match List $I$ with List $II$:
List $I$ (Amines) List $II$ $(pK_{b})$
$A$. Aniline $I$. $3.25$
$B$. Ethanamine $II$. $3.00$
$C$. $N$-Ethylethanamine $III$. $9.38$
$D$. $N,N$-Diethylethanamine $IV$. $3.29$

Choose the correct answer from the options given below:

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Reduction of methyl isocyanide gives:

In the reaction $A$ $\xrightarrow{SnCl_2/HCl} B$ $\xrightarrow{NaNO_2/HCl, 0^{\circ}C} C$ $\xrightarrow{H_2O/\Delta} C_6H_5OH$,what are $A, B$,and $C$?

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