The correct order of ionic radii of trivalent | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The ionic radii of trivalent lanthanide ions ($La^{3+}$ to $Lu^{3+}$) decrease due to lanthanide contraction. $La^{3+}$ $(Z=57)$ has the largest r

Vedclass · Accepted Answer

$Y^{3+} < Lu^{3+} < Eu^{3+} < La^{3+}$

Vedclass · Answer

(C) The ionic radii of trivalent lanthanide ions ($La^{3+}$ to $Lu^{3+}$) decrease due to lanthanide contraction. $La^{3+}$ $(Z=57)$ has the largest radius,while $Lu^{3+}$ $(Z=71)$ has the smallest radius among the lanthanides. $Y^{3+}$ $(Z=39)$ is a $4d$ transition metal ion and is significantly smaller than the $4f$ lanthanide ions. Therefore,the order of ionic radii is $Y^{3+} < Lu^{3+} < Eu^{3+} < La^{3+}$.

The correct order of ionic radii of trivalent ions $Y^{3+}$,$La^{3+}$,$Eu^{3+}$,and $Lu^{3+}$ is $(Y=39, La=57, Eu=63, Lu=71)$.

Similar Questions

Which of the following represents the decreasing order of the second ionization enthalpy $(I.P_2)$?

Choose the correct statement. $Fe^{3+}$ ion is more stable than $Fe^{2+}$ ion because

Which of the following statements is true for transition elements?

Approximately what percentage $(\%)$ of the total elements are transition elements?

The halides of transition elements become more covalent with increasing oxidation state of the metal. Why?

Vedclass Test Series

Exam Paper Generator

Online Exam Module