The correct order of ionic size of N^{3-},Na^ | vedclass

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Question

(C) All the given ions ($N^{3-}$,$O^{2-}$,$F^{-}$,$Na^{+}$,$Mg^{2+}$) are isoelectronic species,meaning they all contain $10$ electrons.For isoelectro

Vedclass · Accepted Answer

$Mg^{2+} < Na^{+} < F^{-} < O^{2-} < N^{3-}$

Vedclass · Answer

(C) All the given ions ($N^{3-}$,$O^{2-}$,$F^{-}$,$Na^{+}$,$Mg^{2+}$) are isoelectronic species,meaning they all contain $10$ electrons.For isoelectronic species,the ionic size decreases as the atomic number $(Z)$ increases because the effective nuclear charge increases,pulling the electrons closer to the nucleus.The atomic numbers are: $N (7)$,$O (8)$,$F (9)$,$Na (11)$,$Mg (12)$.Since $Mg^{2+}$ has the highest atomic number $(12)$,it has the smallest size,and $N^{3-}$ has the lowest atomic number $(7)$,it has the largest size.Therefore,the correct order of increasing ionic size is $Mg^{2+} < Na^{+} < F^{-} < O^{2-} < N^{3-}$.

The correct order of ionic size of $N^{3-}$,$Na^{+}$,$F^{-}$,$Mg^{2+}$,and $O^{2-}$ is:

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