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(D) Lattice energy is directly proportional to the product of the charges of the ions $(q_1 	imes q_2)$ and inversely proportional to the interionic

Vedclass · Accepted Answer

$Al_2O_3 > CaO > MgBr_2 > NaCl$

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(D) Lattice energy is directly proportional to the product of the charges of the ions $(q_1 	imes q_2)$ and inversely proportional to the interionic distance $(r_0)$.For the given compounds,the charges are:$NaCl$: $Na^+$,$Cl^-$ (Product of charges = $1 	imes 1 = 1$)$MgBr_2$: $Mg^{2+}$,$Br^-$ (Product of charges = $2 	imes 1 = 2$)$CaO$: $Ca^{2+}$,$O^{2-}$ (Product of charges = $2 	imes 2 = 4$)$Al_2O_3$: $Al^{3+}$,$O^{2-}$ (Product of charges = $3 	imes 2 = 6$)Comparing the product of charges,the order is $Al_2O_3 (6) > CaO (4) > MgBr_2 (2) > NaCl (1)$.Thus,the correct order of lattice energy is $Al_2O_3 > CaO > MgBr_2 > NaCl$.

The correct order of lattice energy of the following compounds is:

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