The correct order of second ionization potent | vedclass

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Question

(C) The electronic configurations of the elements are: $C (2s^2 2p^2)$,$N (2s^2 2p^3)$,$O (2s^2 2p^4)$,$F (2s^2 2p^5)$.After the removal of the first

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$O > F > N > C$

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(C) The electronic configurations of the elements are: $C (2s^2 2p^2)$,$N (2s^2 2p^3)$,$O (2s^2 2p^4)$,$F (2s^2 2p^5)$.After the removal of the first electron,the configurations become: $C^+ (2s^2 2p^1)$,$N^+ (2s^2 2p^2)$,$O^+ (2s^2 2p^3)$,$F^+ (2s^2 2p^4)$.The second ionization potential involves removing an electron from these cations.$O^+$ has a stable half-filled $2p^3$ configuration,making it the most difficult to remove an electron from.Following the periodic trend and stability,the order of second ionization potential is $O > F > N > C$.

The correct order of second ionization potential of carbon,nitrogen,oxygen and fluorine is

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