The correct order of the bond angles of the c | vedclass

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(D) $BeCl_2$ has a linear structure,so the bond angle is $180^{\circ}$.$BF_3$ has a trigonal planar structure,so the bond angle is $120^{\circ}$.$SiCl

Vedclass · Accepted Answer

$BeCl_2 > BF_3 > SiCl_4 > SF_6$

Vedclass · Answer

(D) $BeCl_2$ has a linear structure,so the bond angle is $180^{\circ}$.$BF_3$ has a trigonal planar structure,so the bond angle is $120^{\circ}$.$SiCl_4$ has a tetrahedral structure,so the bond angle is $109.5^{\circ}$.$SF_6$ has an octahedral structure,so the bond angle is $90^{\circ}$.Therefore,the correct order of bond angles is $BeCl_2 (180^{\circ}) > BF_3 (120^{\circ}) > SiCl_4 (109.5^{\circ}) > SF_6 (90^{\circ})$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A. SF_4$	$I. T\text{-shaped}$
$B. ClF_3$	$II. \text{Square planar}$
$C. BrF_5$	$III. \text{See-saw}$
$D. XeF_4$	$IV. \text{Square pyramidal}$

The correct order of the bond angles of the compounds $SiCl_4, BF_3, BeCl_2$ and $SF_6$ is

Similar Questions

Match the molecules in List-$I$ with their respective shapes in List-$II$.
List-$I$ (Molecule) List-$II$ (Shape)
$A. SF_4$ $I. T\text{-shaped}$
$B. ClF_3$ $II. \text{Square planar}$
$C. BrF_5$ $III. \text{See-saw}$
$D. XeF_4$ $IV. \text{Square pyramidal}$

The correct sequence of decreasing bond angles for the following hydrides is:

Among the following species, the $H - X - H$ bond angle $(X = B, N, \text{ or } P)$ follows the order:

In which of the following molecules are all bonds not equal?

The shape of $XeF^{+}_3$ is

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