The correct order of the decreasing ionic rad | vedclass

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Question

(C) For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.All the given species $(S^{2-}, Cl^{-}, K^{+}

Vedclass · Accepted Answer

$S^{2-} > Cl^{-} > K^{+} > Ca^{2+}$

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(C) For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.All the given species $(S^{2-}, Cl^{-}, K^{+}, Ca^{2+})$ have $18$ electrons.The atomic numbers are: $S (16), Cl (17), K (19), Ca (20)$.As the nuclear charge increases,the force of attraction between the nucleus and the electrons increases,which pulls the electron cloud closer to the nucleus,resulting in a smaller ionic radius.Therefore,the order of decreasing ionic radii is $S^{2-} > Cl^{-} > K^{+} > Ca^{2+}$.

The correct order of the decreasing ionic radii among the following isoelectronic species is

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