The correct order of the oxidation states of nitrogen in $NO$,$N_2O$,$NO_2$,and $N_2O_3$ is:
- A$N_2O < N_2O_3 < NO < NO_2$
- B$NO_2 < NO < N_2O_3 < N_2O$
- C$NO_2 < N_2O_3 < NO < N_2O$
- D$N_2O < NO < N_2O_3 < NO_2$
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Similar Questions
What is the oxidation number of $Cl$ in $HClO_4$ and $HClO_3$?
Easy
View SolutionIn alkaline condition,$KMnO_4$ reacts as follows:
$2KMnO_4 + 2KOH \to 2K_2MnO_4 + H_2O + O$
The equivalent weight of $KMnO_4$ is:
$2KMnO_4 + 2KOH \to 2K_2MnO_4 + H_2O + O$
The equivalent weight of $KMnO_4$ is:
Medium
View SolutionWhat is the change in the oxidation state of $Mn$ in the reaction of $MnO_4^{-}$ with $H_2O_2$ in acidic medium?
Oxidation number of osmium $(Os)$ in $OsO_4$ is
$X + Y \rightarrow$ oleum. The sum of oxidation states of the central atom in $X$ and $Y$ is:
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