The correct order of the rate of reaction of | vedclass

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(C) The rate of $S_{N}1$ reaction is directly proportional to the stability of the carbocation $(C^{\oplus})$ formed.$I$ is $1-$bromobicyclo[$2.2$.$1$

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$II < I < III < IV$

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(C) The rate of $S_{N}1$ reaction is directly proportional to the stability of the carbocation $(C^{\oplus})$ formed.$I$ is $1-$bromobicyclo[$2.2$.$1$]heptane and $II$ is $1-$bromobicyclo[$2.2$.$2$]octane. Both are bridgehead halides and are extremely unreactive in $S_{N}1$ reactions due to Bredt's rule, which prevents the formation of a planar carbocation at the bridgehead position.Between $I$ and $II$, $II$ is slightly more reactive than $I$ because the bridgehead carbocation in $II$ is less strained than in $I$.$III$ is a tert-butyl carbocation, which is more stable than the bridgehead carbocations.$IV$ is a triphenylmethyl carbocation, which is the most stable due to extensive resonance stabilization by three phenyl rings.Thus, the correct order of reactivity is $II < I < III < IV$.

The correct order of the rate of reaction of the following reactants with a nucleophile by $S_{N}1$ mechanism is:
(Given: Structure $I$ and $II$ are rigid)

Similar Questions

Identify the statement which is not correct?

In the given reaction,what is $A$?
$4-methylcyclohexyl bromide + OH^- \xrightarrow{S_N2} A$

The $S_{N}2$ reaction mechanism proceeds through ........

Observe the following reactions:
$1$. $C_6H_5-CH=CH_2 + HBr \rightarrow X$
$2$. $C_6H_5-C(CH_3)=CH_2 + HBr \rightarrow Y$
$3$. $C_6H_5-CH=CH_2 + HBr \xrightarrow{(C_6H_5COO)_2} Z$
The correct order of reactivity of $X, Y, Z$ towards $S_N1$ reaction is:

The product of the reaction will be:

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The correct order of the rate of reaction of the following reactants with a nucleophile by $S_{N}1$ mechanism is:(Given: Structure $I$ and $II$ are rigid)