(C) The bond angle depends on the hybridization of the central atom. For $sp^3$ hybridization,the bond angle is approximately $109.5^o$. For $sp^2$ hy

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(C) The bond angle depends on the hybridization of the central atom. For $sp^3$ hybridization,the bond angle is approximately $109.5^o$. For $sp^2$ hybridization,the bond angle is $120^o$. For $sp$ hybridization,the bond angle is $180^o$. Therefore,the increasing order of bond angle is $sp^3 < sp^2 < sp$.