The correct pair of species with $(A)$ the highest bond order and $(B)$ diamagnetic character is

Which of the following statements are correct for the peroxide ion $(O_{2}^{2-})$?
$(i)$ It has a bond order of $1$.
$(ii)$ It is diamagnetic.
$(iii)$ It has four completely filled antibonding molecular orbitals.
$(iv)$ It is isoelectronic with neon.

In $O_2^-$,$O_2$,and $O_2^{2-}$,the total number of antibonding electrons respectively are:

Match the following:

Pair of species	Identical property
$A$. $B_2 \& O_2$	$P$. Bond order $= 2.5$
$B$. $Be_2 \& H_2^{2-}$	$Q$. Paramagnetic nature
$C$. $N_2^{+} \& N_2^{-}$	$R$. Diamagnetic nature
$D$. $O_2^{+} \& O_2^{-}$	$S$. Doesn't exist

Match List-$I$ with List-$II$.

List-$I$	List-$II$
$A$. $\Psi_{MO} = \Psi_{A} - \Psi_{B}$	$I$. Dipole moment
$B$. $\mu = Q \times r$	$II$. Bonding molecular orbital
$C$. $\frac{N_{b} - N_{a}}{2}$	$III$. Anti-bonding molecular orbital
$D$. $\Psi_{MO} = \Psi_{A} + \Psi_{B}$	$IV$. Bond order

Number of molecules having bond order $2$ from the following molecules is: $C_2, O_2, Be_2, Li_2, Ne_2, N_2, He_2$