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Question

(C) The total magnetic field $(B)$ inside a material is the sum of the magnetic field due to external current $(B_0 = \mu_0 H)$ and the magnetic field

Vedclass · Accepted Answer

$\frac{B}{H}=\mu_0(1+\chi)$

Vedclass · Answer

(C) The total magnetic field $(B)$ inside a material is the sum of the magnetic field due to external current $(B_0 = \mu_0 H)$ and the magnetic field due to magnetization $(B_m = \mu_0 M)$.$B = B_0 + B_m = \mu_0 H + \mu_0 M = \mu_0(H + M)$.Since the magnetization $(M)$ is related to the magnetic intensity $(H)$ by the susceptibility $(\chi)$ as $M = \chi H$,we substitute this into the equation:$B = \mu_0(H + \chi H) = \mu_0 H(1 + \chi)$.Rearranging this gives the ratio:$\frac{B}{H} = \mu_0(1 + \chi)$.

The correct relation between total magnetic field $(B)$,magnetic intensity $(H)$,permeability of free space $(\mu_0)$ and susceptibility $(\chi)$ is

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