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(A) The conversion of $p$-nitrotoluene to $2$-bromo-$4$-methylbenzonitrile involves the following steps:$1$. Bromination: $p$-Nitrotoluene reacts with

Vedclass · Accepted Answer

Bromination,reduction,carbylamine reaction

Vedclass · Answer

(A) The conversion of $p$-nitrotoluene to $2$-bromo-$4$-methylbenzonitrile involves the following steps:$1$. Bromination: $p$-Nitrotoluene reacts with $Br_2$ to form $2$-bromo-$4$-nitrotoluene.$2$. Reduction: The nitro group $(-NO_2)$ is reduced to an amino group $(-NH_2)$ using $Sn + HCl$ to form $2$-bromo-$4$-methylaniline.$3$. Carbylamine reaction: The primary amine $(-NH_2)$ is converted to an isocyanide $(-NC)$ using $CHCl_3 + KOH$ (Note: The final product in the provided image is an isocyanide,not a nitrile,which is characteristic of the carbylamine reaction).Thus,the correct sequence is Bromination,reduction,carbylamine reaction.

The correct sequence of reactions involved in the following conversion is:

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