The correct sequential addition of reagents i | vedclass

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(D) The synthesis of $3-$nitrobenzoic acid from benzene involves the following steps:$1$. Nitration of benzene using $HNO_{3} / H_{2} SO_{4}$ to form

Vedclass · Accepted Answer

$HNO_{3} / H_{2} SO_{4}, Br_{2} / AlBr_{3}, Mg / 	ext{ether}, CO_{2}, H_{3} O^{+}$

Vedclass · Answer

(D) The synthesis of $3-$nitrobenzoic acid from benzene involves the following steps:$1$. Nitration of benzene using $HNO_{3} / H_{2} SO_{4}$ to form nitrobenzene.$2$. Bromination of nitrobenzene using $Br_{2} / AlBr_{3}$ to form $1-$bromo$-3-$nitrobenzene (meta-directing effect of $-NO_{2}$ group).$3$. Formation of Grignard reagent by reacting $1-$bromo$-3-$nitrobenzene with $Mg$ in dry ether to form $3-$nitrophenylmagnesium bromide.$4$. Reaction with $CO_{2}$ followed by acidic hydrolysis $(H_{3} O^{+})$ to yield $3-$nitrobenzoic acid.Thus,the correct sequence is $HNO_{3} / H_{2} SO_{4}, Br_{2} / AlBr_{3}, Mg / 	ext{ether}, CO_{2}, H_{3} O^{+}$.

The correct sequential addition of reagents in the preparation of $3-$nitrobenzoic acid from benzene is:

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