The correct set of four quantum numbers for the valence electron of rubidium atom $(Z=37)$ is:

  • A
    $n=5, l=0, m=0, s=+\frac{1}{2}$
  • B
    $n=5, l=0, m=1, s=+\frac{1}{2}$
  • C
    $n=5, l=1, m=0, s=+\frac{1}{2}$
  • D
    $n=5, l=1, m=1, s=+\frac{1}{2}$

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Similar Questions

The electrons,identified by quantum numbers $n$ and $l$ as $(i) n = 4, l = 1$,$(ii) n = 4, l = 0$,$(iii) n = 3, l = 2$,$(iv) n = 3, l = 1$,can be placed in order of increasing energy,from the lowest to highest,as:

Which of the following combinations of statements is true regarding the interpretation of atomic orbitals?
$1$. An electron in an orbital of high angular momentum stays further away from the nucleus than an electron in an orbital of lower angular momentum.
$2$. For a given value of the principal quantum number, the size of the orbit is inversely proportional to the azimuthal quantum number.
$3$. According to wave mechanics, the ground state angular momentum is equal to $\frac{h}{2\pi}$.
$4$. The plot of $\Psi$ vs $r$ for various azimuthal quantum numbers shows the peak shifting towards higher $r$ values.

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Which electronic level would allow the hydrogen atom to absorb a photon but not to emit a photon?

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