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(C) The electronic configuration of $Cu$ $(Z=29)$ is $[Ar] 3d^{10} 4s^1$.There is only one unpaired electron,which is located in the $4s$ orbital.For

Vedclass · Accepted Answer

$n=4, l=0, m=0, s=+\frac{1}{2}$

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(C) The electronic configuration of $Cu$ $(Z=29)$ is $[Ar] 3d^{10} 4s^1$.There is only one unpaired electron,which is located in the $4s$ orbital.For the $4s$ orbital,the principal quantum number $n=4$.The azimuthal quantum number $l=0$ for an $s$-orbital.The magnetic quantum number $m=0$.The spin quantum number $s$ can be $+\frac{1}{2}$ or $-\frac{1}{2}$.Thus,the correct set of quantum numbers is $n=4, l=0, m=0, s=+\frac{1}{2}$.

The correct set of quantum numbers for the unpaired electron of $Cu$ atom is

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