The correct statement(s) concerning the struc | vedclass

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(C) $E$ is $3$-methylpentan-$2$-one.$F$ and $G$ are enol forms of $E$.$E$ and $F$ are tautomers,and $E$ and $G$ are tautomers. Thus,statement $(B)$ is

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(C) $E$ is $3$-methylpentan-$2$-one.$F$ and $G$ are enol forms of $E$.$E$ and $F$ are tautomers,and $E$ and $G$ are tautomers. Thus,statement $(B)$ is correct.$F$ and $G$ are enol isomers of the same ketone. In $F$,the $-OH$ group and the $-CH_3$ group are on the same side of the double bond (cis-like),while in $G$,they are on opposite sides (trans-like). Thus,$F$ and $G$ are geometrical isomers. Since all geometrical isomers are diastereomers,statements $(C)$ and $(D)$ are also correct.Therefore,the correct statements are $(B), (C)$ and $(D)$.

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