The correct statement about B_{2}H_{6} is | vedclass

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Question

(A) In $B_{2}H_{6}$,the terminal $B-H$ bonds are $sp^{3}$ hybridized,while the bridging $B-H-B$ bonds involve $3c-2e$ (three-center two-electron) bond

Vedclass · Accepted Answer

Terminal $B-H$ bonds have less $p$-character when compared to bridging bonds.

Vedclass · Answer

(A) In $B_{2}H_{6}$,the terminal $B-H$ bonds are $sp^{3}$ hybridized,while the bridging $B-H-B$ bonds involve $3c-2e$ (three-center two-electron) bonds.According to Bent's rule,more $p$-character is directed towards the more electronegative atom or the bond with a smaller bond angle.Since the bond angle $	heta_{2}$ (terminal $H-B-H$) is greater than $	heta_{1}$ (bridging $B-H-B$ angle),the terminal $B-H$ bonds have more $s$-character and less $p$-character compared to the bridging bonds.Thus,option $A$ is correct.$BH_{3}$ is an electron-deficient species and acts as a Lewis acid,not a base.

The correct statement about $B_{2}H_{6}$ is

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