The correct statement among the following is:

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(A) In $(SiH_3)_3N$,the lone pair of electrons on the nitrogen atom is involved in $p\pi-d\pi$ back-bonding with the vacant $d$-orbitals of the silico

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$(SiH_3)_3N$ is planar and less basic than $(CH_3)_3N$

Vedclass · Answer

(A) In $(SiH_3)_3N$,the lone pair of electrons on the nitrogen atom is involved in $p\pi-d\pi$ back-bonding with the vacant $d$-orbitals of the silicon atoms. This results in the molecule adopting a planar geometry ($sp^2$ hybridization). Because the lone pair is delocalized into the $d$-orbitals of silicon,it is not readily available for donation,making $(SiH_3)_3N$ much less basic than $(CH_3)_3N$,where the lone pair is localized on the nitrogen atom.

List-$I$ (Molecule Species)	List-$II$ (Property/Shape)
$A$. $SO_2Cl_2$	$I$. Paramagnetic
$B$. $NO$	$II$. Diamagnetic
$C$. $NO_2^-$	$III$. Tetrahedral
$D$. $I_3^-$	$IV$. Linear

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Match List-$I$ with List-$II$ :

List-$I$ (Molecule Species) List-$II$ (Property/Shape)

$A$. $SO_2Cl_2$ $I$. Paramagnetic

$B$. $NO$ $II$. Diamagnetic

$C$. $NO_2^-$ $III$. Tetrahedral

$D$. $I_3^-$ $IV$. Linear

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