(A) Option $(b)$ is incorrect because the nuclear mass is lower than the mass of its constituents due to the mass defect.Option $(c)$ is incorrect bec

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The $Q$-value of a nuclear process is the difference between final and initial kinetic energies.

(A) Option $(b)$ is incorrect because the nuclear mass is lower than the mass of its constituents due to the mass defect.Option $(c)$ is incorrect because nuclides with the same number of protons are known as isotopes.Option $(d)$ is incorrect because,in nuclear fusion,two or more lighter nuclei combine to form a heavier nucleus.Option $(a)$ is correct because,in a nuclear reaction,the $Q$-value is defined as $Q = K.E_{\text{final}} - K.E_{\text{initial}}$.

Class 12 Physics Nuclei Mass-Energy, Nuclear Binding Energy, Nuclear Stability

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The correct statement of the following is:

AP EAMCET 2022 All AP EAMCET

A
The $Q$-value of a nuclear process is the difference between final and initial kinetic energies.
B
The nuclear mass is always higher than the total mass of its constituents.
C
Nuclides with same number of neutrons in the nucleus are known as isotopes.
D
In nuclear fusion,a heavy nucleus breaks into two smaller fragments.

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Nuclei

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Mass-Energy, Nuclear Binding Energy, Nuclear Stability

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The mass of a proton is $1.0073 \, u$ and that of a neutron is $1.0087 \, u$. The binding energy of $_2He^4$ is .... ($u = \text{atomic mass unit}$,mass of helium nucleus = $4.0015 \, u$)

Difficult

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Degenerate electron pressure will not be sufficient to prevent the core collapse of a white dwarf if its mass becomes $n$ times the solar mass. The value of $n$ is:

MediumAP EAMCET 2005

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Find the binding energy $(BE)$ per nucleon of ${^{56}Fe}$,where $m({^{56}Fe}) = 55.936 \ u$,$m_{n} = 1.00866 \ u$,and $m_{p} = 1.00727 \ u$ (in $MeV$).

MediumAIIMS 2019

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Find the binding energy per nucleon for $^{120}_{50}Sn$. Given: mass of proton $m_{p} = 1.00783 \, U$,mass of neutron $m_{n} = 1.00867 \, U$,and mass of tin nucleus $m_{Sn} = 119.902199 \, U$. (Take $1 \, U = 931 \, MeV$) (in $, MeV$)

MediumJEE MAIN 2020

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The binding energies of $_1H^2$,$_2He^4$,$_{26}Fe^{56}$,and $_{92}U^{235}$ are $2.22 \ MeV$,$28.3 \ MeV$,$492 \ MeV$,and $1786 \ MeV$ respectively. Which nucleus is the most stable?

Medium

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The correct statement of the following is:

Similar Questions

The mass of a proton is $1.0073 \, u$ and that of a neutron is $1.0087 \, u$. The binding energy of $_2He^4$ is .... ($u = \text{atomic mass unit}$,mass of helium nucleus = $4.0015 \, u$)

Degenerate electron pressure will not be sufficient to prevent the core collapse of a white dwarf if its mass becomes $n$ times the solar mass. The value of $n$ is:

Find the binding energy $(BE)$ per nucleon of ${^{56}Fe}$,where $m({^{56}Fe}) = 55.936 \ u$,$m_{n} = 1.00866 \ u$,and $m_{p} = 1.00727 \ u$ (in $MeV$).

Find the binding energy per nucleon for $^{120}_{50}Sn$. Given: mass of proton $m_{p} = 1.00783 \, U$,mass of neutron $m_{n} = 1.00867 \, U$,and mass of tin nucleus $m_{Sn} = 119.902199 \, U$. (Take $1 \, U = 931 \, MeV$) (in $, MeV$)

The binding energies of $_1H^2$,$_2He^4$,$_{26}Fe^{56}$,and $_{92}U^{235}$ are $2.22 \ MeV$,$28.3 \ MeV$,$492 \ MeV$,and $1786 \ MeV$ respectively. Which nucleus is the most stable?

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