The correct statement regarding a carbonyl compound with a hydrogen atom on its $\alpha-$carbon is:

  • A
    $A$ carbonyl compound with a hydrogen atom on its $\alpha-$carbon rapidly equilibrates with its corresponding enol and this process is known as carbonylation.
  • B
    $A$ carbonyl compound with a hydrogen atom on its $\alpha-$carbon rapidly equilibrates with its corresponding enol and this process is known as keto-enol tautomerism.
  • C
    $A$ carbonyl compound with a hydrogen atom on its $\alpha-$carbon never equilibrates with its corresponding enol.
  • D
    $A$ carbonyl compound with a hydrogen atom on its $\alpha-$carbon rapidly equilibrates with its corresponding enol and this process is known as aldehyde-ketone equilibration.

Explore More

Similar Questions

Identify the compound that exhibits tautomerism:

$CH_3-CHO + CH_3-MgBr$ $\rightarrow \text{Product}$ $\xrightarrow{H_2O} A$. What is $A$?

The major product formed in the following reaction is
(Structure of the reactant) $\xrightarrow[{CHCl_3}]{{PCC}}$

Metaformaldehyde is:

Consider the reaction sequence and identify $'C'$.
$A + B \xrightarrow{dil \ NaOH / \Delta} C$
(The reaction sequence is: $3,3-\text{dimethylbut-1-ene} \xrightarrow[(ii) Zn/H_2O]{(i) O_3} A + B$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo