Based on the provided periodic table segment, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The element with atomic number $Z = 52$ is Tellurium $(Te)$,which belongs to group $16$ and period $5$. Following the periodic table structure,the

Vedclass · Accepted Answer

Both $(A)$ and $(B)$.

Vedclass · Answer

(C) The element with atomic number $Z = 52$ is Tellurium $(Te)$,which belongs to group $16$ and period $5$. Following the periodic table structure,the element $X$ is located in group $13$ and period $2$,which is Aluminum $(Al)$. Aluminum oxide $(Al_2O_3)$ is an amphoteric oxide. Amphoteric oxides react with both acids and bases. Therefore,$Al_2O_3$ reacts with $HCl$ (acid) to form $AlCl_3$ and water,and it reacts with $NaOH$ (base) to form sodium aluminate $(NaAlO_2)$ and water. Thus,the correct statement is that it reacts with both $HCl$ and $NaOH$.

Based on the provided periodic table segment,identify the correct statement regarding the oxide of element $X$. The element with atomic number $Z = 52$ is Tellurium $(Te)$.

Similar Questions

The chemical properties of $Li$ and $Mg$ are similar because:

Which of the following is most acidic?

Which of the following represents the correct order of metallic character of the given elements?

How do you determine the chemical reactivity of a compound? Provide an example.

In the periodic table,the metallic character of elements

Vedclass Test Series

Exam Paper Generator

Online Exam Module