The correct statement(s) about the compound H | vedclass

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(A) The compound $X$ is $hexa-2,4-diene-2,5-diol$. It has two chiral centers at $C_2$ and $C_5$ and one double bond at $C_3=C_4$.For the $cis$ isomer

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$(A, D)$

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(A) The compound $X$ is $hexa-2,4-diene-2,5-diol$. It has two chiral centers at $C_2$ and $C_5$ and one double bond at $C_3=C_4$.For the $cis$ isomer ($Z$-isomer),the molecule is symmetrical. The number of stereoisomers is given by $2^{(n-1)} + 2^{(n/2 - 1)} = 2^{(2-1)} + 2^{(2/2 - 1)} = 2^1 + 2^0 = 2 + 1 = 3$.For the $trans$ isomer ($E$-isomer),the molecule is also symmetrical. The number of stereoisomers is $2^{(n-1)} + 2^{(n/2 - 1)} = 2^1 + 2^0 = 3$.Total stereoisomers = $3 (cis) + 3 (trans) = 6$. Thus,$(A)$ is correct.For $cis$ isomer: $2$ enantiomers and $1$ meso compound. Thus,$(D)$ is correct.For $trans$ isomer: $2$ enantiomers and $1$ meso compound. Thus,$(C)$ is incorrect as it states $4$ enantiomers.Since $(A)$ and $(D)$ are correct,the answer is $(A, D)$.

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