The correct structure of product A formed in | vedclass

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(A) The given reaction is a Cannizzaro reaction involving benzaldehyde $(PhCHO)$ in the presence of a base $(NaOD)$ and a deuterated solvent $(D_2O)$.

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(A) The given reaction is a Cannizzaro reaction involving benzaldehyde $(PhCHO)$ in the presence of a base $(NaOD)$ and a deuterated solvent $(D_2O)$.In the mechanism of the Cannizzaro reaction, the hydride ion $(H^-)$ is transferred from the tetrahedral intermediate of one aldehyde molecule to the carbonyl carbon of another aldehyde molecule.Since the reaction is carried out in $D_2O$, the oxygen atom of the hydroxyl group in the resulting alcohol will exchange its hydrogen with deuterium, leading to the formation of an $-OD$ group.However, the hydrogen atom attached to the alpha-carbon of the alcohol $(PhCH_2OD)$ comes from the aldehyde carbon $(PhCHO)$, which does not exchange with the solvent during the hydride transfer step.Therefore, the product formed is benzyl alcohol with a deuterated hydroxyl group, which is $Ph-CH_2-OD$.

The correct structure of product $A$ formed in the following reaction:
$PhCHO + PhCHO \xrightarrow[in\, D_2O]{NaOD} A + PhCOO^{-}$
($Ph$ is $-C_6H_5$)

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The correct structure of product $A$ formed in the following reaction:$PhCHO + PhCHO \xrightarrow[in\, D_2O]{NaOD} A + PhCOO^{-}$($Ph$ is $-C_6H_5$)