The critical angle for light going from mediu | vedclass

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(D) The critical angle $	heta$ is defined for light traveling from a denser medium to a rarer medium. Let medium $A$ be the denser medium and medium

Vedclass · Accepted Answer

$\frac{V_{A}}{\sin 	heta}$

Vedclass · Answer

(D) The critical angle $	heta$ is defined for light traveling from a denser medium to a rarer medium. Let medium $A$ be the denser medium and medium $B$ be the rarer medium.According to Snell's law at the critical angle,the refractive index of medium $A$ with respect to medium $B$ is given by:${}_{B}\mu_{A} = \frac{1}{\sin 	heta}$We also know that the refractive index is the ratio of the speed of light in the two media:${}_{B}\mu_{A} = \frac{V_{B}}{V_{A}}$Equating the two expressions:$\frac{V_{B}}{V_{A}} = \frac{1}{\sin 	heta}$Therefore,the speed of light in medium $B$ is:$V_{B} = \frac{V_{A}}{\sin 	heta}$

The critical angle for light going from medium $A$ into medium $B$ is $\theta$. The speed of light in medium $A$ is $V_A$. What is the speed of light in medium $B$?

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