The crystal field splitting energy of [Co(oxa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The crystal field splitting energy $(\Delta_0)$ for an octahedral complex depends on the oxidation state of the metal ion and the nature of the li

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) The crystal field splitting energy $(\Delta_0)$ for an octahedral complex depends on the oxidation state of the metal ion and the nature of the ligand.For $[Co(oxalate)_3]^{3-}$, the metal is $Co^{3+}$ ($3d^6$ configuration).For $[Cr(oxalate)_3]^{3-}$, the metal is $Cr^{3+}$ ($3d^3$ configuration).Generally, $\Delta_0$ increases with the oxidation state of the metal ion. For the same ligand (oxalate) and same geometry (octahedral), the ratio of splitting energy is primarily determined by the metal ion's charge and electronic configuration.However, in the context of standard coordination chemistry problems comparing these specific complexes, the ratio of the crystal field splitting energy $\Delta_0$ values is found to be $n = 2$.

The crystal field splitting energy of $[Co(oxalate)_3]^{3-}$ complex is '$n$' times that of the $[Cr(oxalate)_3]^{3-}$ complex. Here '$n$' is [Assume $\Delta_0 \gg P$].

Similar Questions

Which relationship is correct for the crystal field splitting energy between octahedral $(\Delta_0)$ and tetrahedral $(\Delta_t)$ complexes?

$[Fe(CN)_{6}]^{3-}$ is an inner orbital complex. Ignoring the pairing energy,the value of crystal field stabilization energy for this complex is $(-)\;\dots \;\Delta_{o}$.

What is the correct electronic configuration of the central atom in $K_{4}[Fe(CN)_{6}]$ based on crystal field theory?

What is crystal field splitting energy? How does the magnitude of $\Delta_{o}$ decide the actual configuration of $d$-orbitals in a coordination entity?

Which of the following is the strongest field ligand?

Vedclass Test Series

Exam Paper Generator

Online Exam Module