The crystalline form of borax has(A) tetranuc | vedclass

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(D) The correct formula of borax is $Na_2\left[B_4O_5(OH)_4\right] \cdot 8H_2O$.$1$. Borax contains a tetranuclear unit $\left[B_4O_5(OH)_4\right]^{2-

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$A, C, D$

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(D) The correct formula of borax is $Na_2\left[B_4O_5(OH)_4\right] \cdot 8H_2O$.$1$. Borax contains a tetranuclear unit $\left[B_4O_5(OH)_4\right]^{2-}$,which consists of two $sp^3$ hybridized boron atoms and two $sp^2$ hybridized boron atoms.$2$. Since there are two $sp^3$ and two $sp^2$ boron atoms,the number of $sp^2$ and $sp^3$ hybridized boron atoms is equal.$3$. In the structure,each of the four boron atoms is bonded to one terminal hydroxide $(-OH)$ group.$4$. The boron atoms are not all in the same plane due to the tetrahedral geometry of the $sp^3$ hybridized boron atoms.Therefore,statements $A$,$C$,and $D$ are correct.

List-$I$	List-$II$
$a$. Borax	$i$. $NaBO_2$
$b$. Kernite	$ii$. $Na_2B_4O_7 \cdot 4H_2O$
$c$. Orthoboric acid	$iii$. $H_3BO_3$
$d$. Borax bead	$iv$. $Na_2B_4O_7 \cdot 10H_2O$

The crystalline form of borax has
$(A)$ tetranuclear $\left[B_4O_5(OH)_4\right]^{2-}$ unit
$(B)$ all boron atoms in the same plane
$(C)$ equal number of $sp^2$ and $sp^3$ hybridized boron atoms
$(D)$ one terminal hydroxide per boron atom

Similar Questions

Match List-$I$ with List-$II$:

List-$I$ List-$II$

$a$. Borax $i$. $NaBO_2$

$b$. Kernite $ii$. $Na_2B_4O_7 \cdot 4H_2O$

$c$. Orthoboric acid $iii$. $H_3BO_3$

$d$. Borax bead $iv$. $Na_2B_4O_7 \cdot 10H_2O$

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The crystalline form of borax has$(A)$ tetranuclear $\left[B_4O_5(OH)_4\right]^{2-}$ unit$(B)$ all boron atoms in the same plane$(C)$ equal number of $sp^2$ and $sp^3$ hybridized boron atoms$(D)$ one terminal hydroxide per boron atom