The current $I$ flowing through the given circuit will be $.....A$.

$A$ conductor of resistance $3 \Omega$ is stretched uniformly until its length is doubled. The wire is now bent in the form of an equilateral triangle. The effective resistance between the ends of any side of the triangle in ohms is

$A$ Copper $(Cu)$ rod of length $25 \, cm$ and cross-sectional area $3 \, mm^2$ is joined with a similar Aluminium $(Al)$ rod as shown in the figure. Find the resistance of the combination between the ends $A$ and $B$ (in $m\Omega$).
(Take Resistivity of Copper $= 1.7 \times 10^{-8} \, \Omega \cdot m$,Resistivity of Aluminium $= 2.6 \times 10^{-8} \, \Omega \cdot m$)

Two resistors are joined in parallel,and their resultant resistance is $\frac{6}{5} \,\Omega$. One of the resistance wires is broken,and the effective resistance becomes $2 \,\Omega$. Then the resistance (in $\Omega$) of the wire that got broken is ..........

Calculate the equivalent resistance across $A-B$ in the given circuit. ............... $\Omega$

Two resistors of resistance $R_1$ and $R_2$ having $R_1 > R_2$ are connected in parallel. For equivalent resistance $R$,the correct statement is: