The current $(I)$ in the inductance is varying with time according to the plot shown in the figure. Which one of the following is the correct variation of voltage $(V)$ with time in the coil?

$A$ current $I = 10 \ A$ is passed through the part of a circuit shown in the figure. What will be the potential difference between $A$ and $B$ when $I$ is decreased at a constant rate of $10^2 \ A \ s^{-1}$ (in $V$)?

The current $i$ in a coil varies with time as shown in the figure. The variation of induced $emf$ with time would be:

The network shown in the figure is part of a complete circuit. If at a certain instant the current $i$ is $5 \, A$ and is decreasing at the rate of $10^3 \, A/s$, then $V_B - V_A$ is: (in $ \, V$)

Two different coils have self-inductance $L_1 = 8 \, mH$ and $L_2 = 2 \, mH$. The current in both coils is increased at the same constant rate. At a certain instant of time,the power supplied to the two coils is the same. At that time,the current,induced voltage,and energy stored in the first coil are $i_1, V_1$,and $W_1$ respectively. Corresponding values for the second coil at the same instant are $i_2, V_2$,and $W_2$ respectively. Then:

$A$ square metal loop of side $10 \, cm$ and resistance $1 \, \Omega$ is moved with a constant velocity partly inside a magnetic field of $2 \, Wb \cdot m^{-2}$,directed into the paper,as shown in the figure. This loop is connected to a network of five resistors each of value $3 \, \Omega$. If a steady current of $1 \, mA$ flows in the loop,then the speed of the loop is ..... $cm \cdot s^{-1}$.