The current in a simple series circuit is $5.0 \, A$. When an additional resistance of $2.0 \, \Omega$ is inserted, the current drops to $4.0 \, A$. The original resistance of the circuit in $\Omega$ was:

In the given circuit,find the current in each resistance. (in $A$)

Three equal resistances each of value $R$ are joined as shown in the figure. The equivalent resistance between $M$ and $N$ is

Three resistors of $4\,\Omega$,$6\,\Omega$,and $12\,\Omega$ are connected in parallel,and the combination is connected in series with a $1.5\,V$ battery of $1\,\Omega$ internal resistance. The rate of Joule heating in the $4\,\Omega$ resistor is ................ $W$.

Consider the circuits shown in the figure. Both the circuits draw the same current from the battery,but the current through $R$ in the second circuit is $\frac{1}{10}$th of the current through $R$ in the first circuit. If $R = 11 \ \Omega$,the value of $R_1$ is ................ $\Omega$.

As shown in the figure,a network of resistors is connected to a battery of $24\,V$ with an internal resistance of $3\,\Omega$. The currents through the resistors $R_4$ and $R_5$ are $I_4$ and $I_5$ respectively. The values of $I_4$ and $I_5$ are: