The current in the arm CD of the circuit will | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction must equal the sum of currents leaving it.At junction $A$,the

Vedclass · Accepted Answer

$i_2 + i_3$

Vedclass · Answer

(B) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction must equal the sum of currents leaving it.At junction $A$,the current $i_1$ enters and splits into $i_2$ and $i_3$,so $i_1 = i_2 + i_3$.Now,consider the junction $C$. The current $i_3$ arrives at $C$ from branch $AC$. The current $i_2$ flows through the branch $AB$ and then through the branch $BC$ to reach junction $C$.Therefore,the total current entering junction $C$ is $i_2 + i_3$.This combined current then flows through the arm $CD$.Thus,the current in the arm $CD$ is $i_2 + i_3$.

The current in the arm $CD$ of the circuit will be

Similar Questions

For the circuit shown below,write the equations for the three loops by using Kirchhoff's loop rule.

Five resistances are connected as shown in the figure. The effective resistance between points $A$ and $B$ is

When the value of $R$ in the balanced Wheatstone bridge, shown in the figure, is increased from $5 \Omega$ to $7 \Omega$, the value of $S$ has to be increased by $3 \Omega$ in order to maintain the balance. What is the initial value of $S$ (in $\Omega$)?

In the circuit shown,what is the potential difference $V_{PQ}$?

For the circuit shown,with $R_1 = 1.0\,\Omega$,$R_2 = 2.0\,\Omega$,$E_1 = 2\,V$ and $E_2 = E_3 = 4\,V$,the potential difference between the points $a$ and $b$ is approximately (in $V$):

Vedclass Test Series

Exam Paper Generator

Online Exam Module