The curve between absolute temperature T and | vedclass

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(B) The root mean square speed of gas molecules is given by the formula: $v_{rms} = \sqrt{\frac{3RT}{M}}$ Squaring both sides,we get: $v_{rms}^2 = \fr

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(B) The root mean square speed of gas molecules is given by the formula: $v_{rms} = \sqrt{\frac{3RT}{M}}$ Squaring both sides,we get: $v_{rms}^2 = \frac{3RT}{M}$ Since $R$ (universal gas constant) and $M$ (molar mass of the gas) are constants,we can write: $v_{rms}^2 \propto T$ This equation represents a linear relationship of the form $y = mx$,where $y = v_{rms}^2$,$x = T$,and the slope $m = \frac{3R}{M}$. Therefore,the graph between $v_{rms}^2$ and $T$ is a straight line passing through the origin. This corresponds to graph $B$.

The curve between absolute temperature $T$ and ${v^2}_{rms}$ is

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