The curved surface area of a cone is 85 pi , | vedclass

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(C) For the given cone,the radius $r = \frac{	ext{diameter}}{2} = \frac{10}{2} = 5 \, cm$.The curved surface area $(CSA)$ of a cone is given by the f

Vedclass · Accepted Answer

$17$

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(C) For the given cone,the radius $r = \frac{	ext{diameter}}{2} = \frac{10}{2} = 5 \, cm$.The curved surface area $(CSA)$ of a cone is given by the formula $CSA = \pi r l$,where $l$ is the slant height.Given that $CSA = 85 \pi \, cm^{2}$,we have:$85 \pi = \pi 	imes 5 	imes l$Dividing both sides by $5 \pi$:$l = \frac{85 \pi}{5 \pi} = 17 \, cm$.Therefore,the slant height of the cone is $17 \, cm$.

The curved surface area of a cone is $85 \pi \, cm^{2}$. If its diameter is $10 \, cm$,its slant height is $\dots \dots \dots \dots \, cm$.

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