The curved surface area of a cylindrical well | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $r$ be the radius and $h$ be the depth of the cylindrical well.The curved surface area is given by $2 \pi r h = 264 \, m^2$ $... (1)$The volum

Vedclass · Accepted Answer

$14, 6$

Vedclass · Answer

(A) Let $r$ be the radius and $h$ be the depth of the cylindrical well.The curved surface area is given by $2 \pi r h = 264 \, m^2$ $... (1)$The volume is given by $\pi r^2 h = 924 \, m^3$ $... (2)$Dividing equation $(2)$ by equation $(1)$:$\frac{\pi r^2 h}{2 \pi r h} = \frac{924}{264}$$\frac{r}{2} = 3.5$$r = 7 \, m$Therefore,the diameter $d = 2r = 14 \, m$.Substituting $r = 7$ in equation $(1)$:$2 	imes \frac{22}{7} 	imes 7 	imes h = 264$$44 	imes h = 264$$h = \frac{264}{44} = 6 \, m$.Thus,the diameter is $14 \, m$ and the depth is $6 \, m$.

The curved surface area of a cylindrical well is $264 \, m^2$ and its volume is $924 \, m^3$. What are the diameter and the depth of the well? (in $m$)

Similar Questions

The volume of a cube is $729 \, cm^3$. The total surface area of the cube is ........ $cm^2$.

How many cubes of $10\, cm$ edge can be put in a cubical box of $1\, m$ edge?

The base of a right prism is an equilateral triangle with a side of $6 \, cm$. If the volume of the prism is $108 \sqrt{3} \, cm^3$,its height is ...... $cm$.

If a sphere of radius $r$ is divided into $4$ identical parts,then the total surface area of the $4$ parts is

The material of a cone is converted into the shape of a cylinder of equal radius. If the height of the cylinder is $5\, cm$,the height of the cone is........$cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module