The cyanide ion,CN^{-} and N_2 are isoelectro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Both $CN^{-}$ and $N_2$ are isoelectronic,having $14$ electrons each and a triple bond between the atoms. However,$N_2$ is a homonuclear diatomic

Vedclass · Accepted Answer

Absence of bond polarity

Vedclass · Answer

(B) Both $CN^{-}$ and $N_2$ are isoelectronic,having $14$ electrons each and a triple bond between the atoms. However,$N_2$ is a homonuclear diatomic molecule,meaning it has no bond polarity (the electronegativity difference is zero). In contrast,$CN^{-}$ is a heteronuclear ion with a significant difference in electronegativity between $C$ and $N$,resulting in a polar bond. The absence of bond polarity in $N_2$ makes it chemically inert compared to $CN^{-}$.

The cyanide ion,$CN^{-}$ and $N_2$ are isoelectronic. But in contrast to $CN^{-}$,$N_2$ is chemically inert because of

Similar Questions

Which molecule has the largest dipole moment?

Show the dipole moment of $H_2O$ and $BeH_2$ with diagrams.

Identify the option in which the molecules are arranged in the correct order of their dipole moments.

The correct order of dipole moment for $o$-nitrophenol $(I)$ and $o$-dichlorobenzene $(II)$ is ......

Explain the dipole moment of a triatomic molecule $(AB_2)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module