The de-Broglie wavelength of a tennis ball of mass $60 \ g$ moving with a velocity of $10 \ ms^{-1}$ is approximately . . . . . . (Planck's constant $h = 6.63 \times 10^{-34} \ J \cdot s$).
- A$1.1 \times 10^{-31} \ m$
- B$1.1 \times 10^{-33} \ m$
- C$1.1 \times 10^{-34} \ m$
- D$1.1 \times 10^{-32} \ m$
Explore More
Similar Questions
What is the characteristic of an electron microscope? On which principle is it based?
Easy
View SolutionThe wavelength of an electron of kinetic energy $4.50 \times 10^{-29} \ J$ is $... \times 10^{-5} \ m$. (Nearest integer) Given: mass of electron is $9 \times 10^{-31} \ kg$,$h = 6.6 \times 10^{-34} \ J \ s$.
Two particles of masses $m$ and $2m$ have equal kinetic energies. The de-Broglie wavelengths are in the ratio of
Calculate the de-Broglie wavelength of an electron travelling at $1\%$ of the speed of light.
Difficult
View SolutionThe wavelength of the electron emitted by a metal sheet of work function $4 \ eV$ when photons from $EMR$ of wavelength $124 \ nm$ strike the metal plate is ........... $nm$.
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo