The de-Broglie wavelength of a tennis ball of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The de-Broglie wavelength is given by the formula $\lambda = \frac{h}{mv}$.Given:Mass $m = 60 \, g = 60 	imes 10^{-3} \, kg = 0.06 \, kg$.Velocit

Vedclass · Accepted Answer

$10^{-33} \, m$

Vedclass · Answer

(A) The de-Broglie wavelength is given by the formula $\lambda = \frac{h}{mv}$.Given:Mass $m = 60 \, g = 60 	imes 10^{-3} \, kg = 0.06 \, kg$.Velocity $v = 10 \, m/s$.Planck's constant $h = 6.63 	imes 10^{-34} \, J \cdot s$.Substituting the values:$\lambda = \frac{6.63 	imes 10^{-34}}{0.06 	imes 10} = \frac{6.63 	imes 10^{-34}}{0.6} \approx 1.1 	imes 10^{-33} \, m$.Thus,the value is approximately $10^{-33} \, m$.

The de-Broglie wavelength of a tennis ball of mass $60 \, g$ moving with a velocity of $10 \, m/s$ is approximately

Similar Questions

The basis of the quantum mechanical model of an atom is:

If the kinetic energy of an electron of mass $9.0 \times 10^{-31} \ kg$ is $8.0 \times 10^{-25} \ J$,the wavelength of this electron in $nm$ is

The minimum de-Broglie wavelength is associated with which of the following?

The kinetic energy of an electron is $4.55 \times 10^{-25} \ J$. Find its wavelength.

The wave nature of an electron was first given by

Vedclass Test Series

Exam Paper Generator

Online Exam Module